Energy Creation by Use of a Coherent Preparation in a Classical Energy Transfer Protocol
© Thomas Alexander Meyer
In this energy creation protocol we use a classical energy-transfer protocol (where the system is decohered and thus is explainable with classical mechanics) with the simple modification of adding a channel of energy transfer that is prepared for a coherent quantum mechanical system which propagates in the absence of energy loss. In all historical energy transfer and storage protocols it is always the case that the preparation of the protocol only allows the system to be in a decohered state which is describable with classical mechanical law. This is why all such protocols are assumed to support the laws of thermodynamics (classical laws) and the laws of conservation of energy and momentum. When one prepares an energy protocol in a decohered manner then one should expect that the protocol follows the laws of thermodynamics, however, if one prepares the protocol in a manner that the system is allowed to be coherent (to be quantum mechanical) then one has the advantage of the assumed properties of a quantum mechanical system, namely the property of propagation in the absence of energy loss. In a decohered preparation, the system must experience loss while propagating.
So how do we propose to define our protocol such that this feature of coherent systems is utilized for the purpose of energy creation? Well, let's use the example of electrical conduction in series with an optical transfer. We consider the setup of Figure 1 where we have a conducting metal adjacent to an optical cavity which we have shown in a layered illustration. The metal layer can be any metal as long as it allows electrical conduction. The optical cavity layer is one which allows electromagnetic radiation to enter from the metal. However, it cannot be the case that electrons may enter the cavity by the photoelectric effect from the surface of the metal.
When electrons are promoted to the conduction band they must absorb an energy (photons and phonons) equal to the band gap of the material, and when the electrons return to valence energy they will emit photons and phonons equal to the band gap energy. So the electrons of the conducting metal will constantly be releasing photons into the optical cavity with an energy that is equal to the bandgap or smaller. Another part of the preparation of the optical cavity is that it must have an optical diode in the middle of the cavity which only allows the light to propagate in one direction (for the purposes of our illustration we have indicated the diode allows propagation from right to left). The bottom layer material in Figure 1 is an adiabatic wall that does not allow electrical or electromagnetic radiation to pass, so no energy may pass this wall through the bottom of the conducting layer. The top layer is similar to this, it is a 100% reflective layer (reflecting downward towards the optical cavity) so that the photons in the optical cavity may not pass this mirror. So all the photonic and electrical activity is confined to the corresponding optical and metalic layers. Since the optical cavity layer has a diode, for the photons that exit the conductor on the right side and then pass through the diode, these photons may only re-enter the metal at a position on the left side of the metal. This implies that any photons emitted into the optical cavity by a current carrier on the right side of the conducting layer can only be used to promote a different electron to current carrier at a position on the right of the metal layer. This means that "on average" energy is propagating in a direction which is from right to left through the optical cavity, and in turn this energy is neutralizing the potential difference of electron and hole pair on the right side and adding a potential difference between electron and hole on the left side. So the current carrying status for an electron and hole has been displaced from right to left.
On average this displacement will result in a net conduction of electrical flow in the direction from left to right. This is my intuitive guess, because energy is moved from right to left in the optical cavity so this must be equalled by a return of energy from left to right through the metal in the form of electrical current, I. This current is actually a net movement of holes towards the right and electrons to the left. However, the status of current carrying (the electrons in the conduction band) must have a net movement from left to right. Even though there is a net movement of electrons from right to left, there is also a net movement of "the total number of conduction band electrons" from left to right.
So it would seem that there is a perpetual motion occurring here. Quantum mechanics predicts that there will always be an average amount of photons being emitted out of the metal and into the optical cavity (and we assume no photoelectric effect). So there will always be an average amount of photons going through the optical diode resulting in an energy flow from right to left in the optical cavity. This energy flow has to be returned through the electrical channel. So why does this happen? Because the optical cavity is a coherent quantum mechanical preparation unlike the metal channel. The optical channel is prepared for a specific bandwidth of photons, it is a preparation for a quantum mechanical system with a well known description. So when the system enters this channel (the photons) then they propagate like a quantum mechanical system always does, at the speed of light and in the absence of loss. However with the classical system, the electrical conduction channel through the metal that completes our circuit, this system is decohered. This system obeys the laws of thermodynamics and this system needs to experience loss when propagating. The quantum mechanical nature of the optical channel is the driving force for perpetual motion in the two channel cycle and the classical mechanical nature of the electrical channel is the liberation of the energy in this cycle of Figure 1.
If indeed my assumptions of this preparation are correct, and there is a perpetual motion incurred (which may be very small and only results from an average emission of photons) then this motion may be used to drive a motor which may use this energy. The energy may in this case be extracted by using the electrical channel as a driving mechanism.
The obvious criticism of this protocol is that it uses an optical diode which is actually a series of polarizers and a Faraday rotator. The polarizers will absorb all light that does not pass, which includes the light that tries to make it back. So light may eventually make it back to the right side by virtue of absorption and re-emission by the polarizers. In addition, the Faraday rotator and the whole diode has a performance which is only optimal for a specific frequency spectrum. These two constraints make for a very small portion of light being subject to the diode's preferred direction.
Assuming that the diode is not operational for a given amount of light due to these constraints, we still have an amount of light which the diode will operate properly for. The idea is to have the cavity mirrors set up to reflect light downwards toward the metal after it passes the diode to the left side. This gives the light an option, either get back to the right side by virtue of the slow process through the diode (in the left to right direction) which requires absorption and re-emission by the polarizer (which is nearly non-conducting) or to go back to the right side by being absorbed at the metal and making it back via conduction of the metal (which is highly conducting). As long as there is a "preference" in the propagation direction of light through the diode (from right to left) then there will be a cycle of energy induced in the loop, as long as the metallic path back is preferential to the "reverse optical diode path" back to the right side.
This page, Propagation Protocol, was started on July 11, 2013. It was modified on July 12-13,16, 2013.